SOLUTION: A pond has 2000 fish in it due to a harmful bacteria the fish are dying at a rate of 15% per day write an equation in the form y=a(b)^t .how many fish will there be in the pond in

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Question 755829: A pond has 2000 fish in it due to a harmful bacteria the fish are dying at a rate of 15% per day write an equation in the form y=a(b)^t .how many fish will there be in the pond in 10 days? How long will it take for half of the fish to die?
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Q:
A pond has 2000 fish in it due to a harmful bacteria the fish are dying at a rate of 15% per day write an equation in the form y=a(b)^t .how many fish will there be in the pond in 10 days? How long will it take for half of the fish to die?
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A:
Equation: highlight%28y+=+2000%280.85%29%5Et%29
In 10 days, there will be 2000%280.85%5E10%29 ≈ highlight%28394%29 number of fish.
2000%280.85%29%5Et+=+1000
0.85%5Et = 1%2F2
t = log%280.85%2C+%281%2F2%29%29 = highlight%284.265%29 days
It will take highlight%284.265%29 days for half of the fish to die.