SOLUTION: There are 10 boys and 22 girls. 5 of them are randomly picked, which should include 3 boys and 2 girls. Find the probability that a boy named Peter is selected.
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Question 755636: There are 10 boys and 22 girls. 5 of them are randomly picked, which should include 3 boys and 2 girls. Find the probability that a boy named Peter is selected. Found 2 solutions by stanbon, Engineer764:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! There are 10 boys and 22 girls. 5 of them are randomly picked, which should include 3 boys and 2 girls. Find the probability that a boy named Peter is selected.
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# of ways to succeed in choosing 2 boys including Peter: 1C1*9C2 = 36
# of ways to succeed in choosing 2 girls: 22C2 = 231
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# of ways to pick 3boys and 2 girls including Peter: 36*231
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# of random ways of pick 5 children: 32C5 = 201,376
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P(condition) = (36*231)/(201,376) = 0.0413
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Cheers,
Stan H.
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