SOLUTION: Q1 THE INTERIOR ANGLE OF REGULAR POLYGON EXCEEDS ITS EXTERIOR ANGLE BY 108 HOW MANY SIDES DOES THE POLYGON HAVE?

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Question 755596: Q1 THE INTERIOR ANGLE OF REGULAR POLYGON EXCEEDS ITS EXTERIOR ANGLE BY 108 HOW MANY SIDES DOES THE POLYGON HAVE?
Answer by reviewermath(1029) About Me  (Show Source):
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Q:
The Interior Angle Of Regular Polygon Exceeds Its Exterior Angle By 108. How Many Sides Does The Polygon Have?
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A:
Let x = measure of each exterior angle
So x + 108 = measure of each interior angle
x + (x + 108) = 180
2x + 108 = 180
2x = 72
x = 36
The number of sides is equal to 360/36 = highlight%2810%29 sides