SOLUTION: If the sum of two numbers is 120, and thier difference is 42, find the smaller number.
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Question 755492
:
If the sum of two numbers is 120, and thier difference is 42, find the smaller number.
Answer by
Cromlix(4381)
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x + y = 120
x - y = 42
Add
2x = 162
x = 81
120 - 81 = 39
81 + 39 = 120
81 - 39 = 42
Two numbers 81 and 39
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