SOLUTION: 1/3[log3(x+2)-2log3x] I got: log3(x+2)^1/3-log3x^2 =log3(x+2/x^2)^1/3
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-> SOLUTION: 1/3[log3(x+2)-2log3x] I got: log3(x+2)^1/3-log3x^2 =log3(x+2/x^2)^1/3
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Question 755460
:
1/3[log3(x+2)-2log3x]
I got: log3(x+2)^1/3-log3x^2
=log3(x+2/x^2)^1/3
Answer by
josmiceli(19441)
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