Question 755355: If angles of a polygon are (x+10),(x+60),2x,and x find x
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! If angles of a polygon are (x+10),(x+60),2x,and x find x
there are four angles and we have a quadrilateral which is a polygon.
the sum of the interior angles of any polygon is (n-2)*180 where n is the number of sides of the polygon
in our case n=4 and so the sum is (4-2)*180 = 360, therefore
(x+10) +(x+60) +2x +x =360
x+10+x+60+2x+x = 360
5x+70=360
5x=290
x=58
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