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Question 755169: I have x+3y-3=0. I figured out how to turn it into the correct equation of y=-1/3x+1. We are told to graph three points. We are given x= -3 for one point; x=0 for point two; and x=3 for third point. We then need to figure for the y-intercept with each of the three x-intercepts. I understand that the first one is (-3, 0); point two is (0, 1); and point three is (3, 2). However, my text shows me no math, therefore, I have no idea how they came up with the y-intercepts. My math on other problems like this end up with the wrong y-intercepts. I need to know how to do the math to get the correct y-intercept.
Thank you,
Angi Campbell @ broquellemo1968@yahoo.com
Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website!
I have x+3y-3=0. I figured out how to turn it into the correct equation of y=-1/3x+1. We are told to graph three points. We are given x= -3 for one point; x=0 for point two; and x=3 for third point. We then need to figure for the y-intercept with each of the three x-intercepts. I understand that the first one is (-3, 0); point two is (0, 1); and point three is (3, 2). However, my text shows me no math, therefore, I have no idea how they came up with the y-intercepts. My math on other problems like this end up with the wrong y-intercepts. I need to know how to do the math to get the correct y-intercept.
Thank you,
Angi Campbell @ broquellemo1968@yahoo.com
x + 3y - 3 = 0 ----- 3y = - x + 3 ----- 
x = - 3 ; y = 2. Coordinate point: (- 3, 2)
x = 0 ; y = 1. Coordinate point: (0, 1)
x = 3 ; y = 0. Coordinate point: (3, 0)
You now have your 3 points that you need to graph, so "connect the dots," or draw a line through the 3 points.
The y-intercept is the coordinate point where the linear graph intersects the y-axis. This is also the coordinate point where the x-value is 0. It should be realized also that anywhere on the y-axis, the x-value is 0. This means that the y-intercept is: ( , ), where it's seen that the x-value is 0 while the y-value is 1.
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