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Question 755098: How to work this problem
-5(1-2z)+4(3-z)=7(3+2)
I have work this problem for a while and I still can't get it please help
Answer by pragya.ban@gmail.com(32)   (Show Source):
You can put this solution on YOUR website! -5(1-2z)+4(3-z)=7(3+2)
The basic idea of this equation is to distribute everything first.
(Remember the Order of Operations: [P]arenthesis [E]xponents [M]ultiplication [D]ivision [A]ddition [S]ubtraction)
1. If you distribute, it should look like this:
-5+10z+12-4z= 7(5)
*The negative sign from -2z changes to a positive sign because when two negative numbers multiply (-5 and -2z in this case), they result in a positive answer (+10z). However, when there is one negative number (-z) and one positive number (+4) multiplied, it equals to a negative answer (-4z).*
2. The next step is to group like terms together and operate in between them:
(-5+12)+(10z-4z)=35
7+6z=35
3. Now solve like normal. Subtract 7 from both sides and then divide by 6.
6z=35-7
z=28/6
z=4.66
To check your answer replace z with 4.66 and see if it equals to 35.
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