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Question 755031: Find the vertex, focus and directrix of a parabola represented by the equation (x-3)^2=-8(y=2)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex, focus and directrix of a parabola represented by the equation
(x-3)^2=-8(y-2)
This is an equation of a parabola that opens downward.
Its basic equation: (x-h)^2=-4p(y-k)
For given equation:
vertex: (3,2)
axis of symmetry: x=3
4p=8
p=2
focus: (3,0) (p units below vertex on the axis of symmetry)
directrix: y=4 (p units above vertex on the axis of symmetry)
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