Question 754979: On the average, 4 out of 5 of the people who register for a fitness program work hard to achieve intended results. If 4 registered patrons were selected at random, what is the probability that more than 2 will be ones who have worked hard to achieve their intended goals?
This is out of a total of 70 patron, 16 male patrons are achieving their intended results, while 7 are not, and 22 female patrons are achieving their intended results, while 25 are not.
If 4 registered patrons were selected at random, what is the probability that more than 2 will be ones who have worked hard to achieve their intended goals?
Please show your work.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! On the average, 4 out of 5 of the people who register for a fitness program work hard to achieve intended results. If 4 registered patrons were selected at random, what is the probab1ility that more than 2 will be ones who have worked hard to achieve their intended goals?
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Binomial Problem with n = 4 and p(work hard) = 4/5 = 0.8
P(3<= x <=4) = 1 - P(0<= x <=2) = 1 - binomcdf(4,0.8,2) = 0.8192
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This is out of a total of 70 patron, 16 male patrons are achieving their intended results, while 7 are not, and 22 female patrons are achieving their intended results, while 25 are not.
What is the question?
Cheers,
Stan H.
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