SOLUTION: solve for x to the nearest second in the interval [180,270] Csc x= -1.8762

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Question 754947: solve for x to the nearest second in the interval [180,270] Csc x= -1.8762
Answer by solver91311(24713) About Me  (Show Source):
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Take the reciprocal of 1.8762 on your calculator. That is the sine of the angle in the first quadrant. Use your calculator to find the inverse sine, that is to say the angle in degrees whose sine is the reciprocal of the cosecant. Since you are looking in the third quadrant, add 180 to that angle. You should have something that looks like 212.2078.... Now you need to convert the decimal fraction of a degree to minutes and seconds. First subtract the whole degrees leaving you with 0.2078..., then multiply by 60. You get something that looks like 12.4710..., which is minutes and decimal parts of minutes. Subtract the whole number part and multiply by 60 again. Seconds are the whole number part (rounded appropriately). You should have 28.2629...ish. Round to the nearest second, 28. So 212 degrees, 12 minutes, 28 seconds.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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