SOLUTION: Algebra-
Here is a solution to this problem. Where is the mistake? Correct it and give the right answer.
3(y + 4) -42= 2y + 3(y+4) +10
3y +12-42=2y +3y +12 +10
3y -30 =5y +2
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Here is a solution to this problem. Where is the mistake? Correct it and give the right answer.
3(y + 4) -42= 2y + 3(y+4) +10
3y +12-42=2y +3y +12 +10
3y -30 =5y +2
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Question 754635: Algebra-
Here is a solution to this problem. Where is the mistake? Correct it and give the right answer.
3(y + 4) -42= 2y + 3(y+4) +10
3y +12-42=2y +3y +12 +10
3y -30 =5y +22
3y -30 +30 = 5y +22 -30
3y =5y -8
3y -5y =5y - 5y -8
-2y/-2 = -8/-2
y=-4 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Here is a solution to this problem. Where is the mistake? Correct it and give the right answer.
3(y + 4) -42 = 2y + 3(y+4) +10
3y +12-42 = 2y +3y +12 +10
3y -30 = 5y + 22
3y -30 +30 = 5y +22 -30 ****** 30 added to one side, -30 to the other.
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3y =5y -8
3y -5y =5y - 5y -8
-2y/-2 = -8/-2
y=-4
