SOLUTION: x-y+z=1 3x+y-2z=-3 x+4y-z=2

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Question 754410: x-y+z=1
3x+y-2z=-3
x+4y-z=2
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x-y+z=1
3x+y-2z=-3
x+4y-z=2
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--> (0,-1,-2)
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I use determinants.
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You can use elimination.
Add eqn 1 & 3, then add eqn1*2 to eqn 3.
That gives 2 eqns in x & y.
etc.