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Question 754253: Is the formula Asub(n)=-4n(n-1) Explicit or recursive? Find the first 5 terms of the sequence.
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! It is explicit since you can find any term you want by plugging in that value for n.
Ex: You can find the 10th term by plugging in n = 10. You do NOT need to know the previous term(s) to find the 10th term. So it's NOT recursive.
Let's find the first 5 terms
Term #1
Asub(n) = -4n(n-1)
Asub(1) = -4(1)(1-1) ... plug in n = 1
Asub(1) = -4(1)(0)
Asub(1) = -4(0)
Asub(1) = 0
Term #1 is 0
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Term #2
Asub(n) = -4n(n-1)
Asub(2) = -4(2)(2-1) ... plug in n = 2
Asub(2) = -4(2)(1)
Asub(2) = -8(1)
Asub(2) = -8
Term #2 is -8
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Term #3
Asub(n) = -4n(n-1)
Asub(3) = -4(3)(3-1) ... plug in n = 3
Asub(3) = -4(3)(2)
Asub(3) = -12(2)
Asub(3) = -24
Term #3 is -24
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Term #4
Asub(n) = -4n(n-1)
Asub(4) = -4(4)(4-1) ... plug in n = 4
Asub(4) = -4(4)(3)
Asub(4) = -16(3)
Asub(4) = -48
Term #4 is -48
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Term #5
Asub(n) = -4n(n-1)
Asub(5) = -4(5)(5-1) ... plug in n = 5
Asub(5) = -4(5)(4)
Asub(5) = -20(4)
Asub(5) = -80
Term #5 is -80
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The first five terms are: 0, -8, -24, -48, -80,
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