SOLUTION: 3(x^2-4)=4(x-3)
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Question 754171
:
3(x^2-4)=4(x-3)
Answer by
Cromlix(4381)
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3(x^2 - 4) = 4(x - 3)
3x^2 - 12 = 4x - 12
3x^2 - 4x - 12 + 12 = 0
3x^2 - 4x = 0
x(3x - 4) = 0
x = 0 or x = 4/3