Question 754067: What are the discontinuities and asyomptotes of (x-2)(x+1)/(x+1)(x-3)
Answer by Peter14(2)   (Show Source):
You can put this solution on YOUR website! Discontinuities and asymptotes come up because you can't divide by zero. Discontinuities are where the same factor appears in both the numerator and the denominator, asymptotes are where a factor appears only in the denominator.
Observe that the denominator of the rational function is (x+1)(x-3). Of these two factors, (x+1) also appears in the numerator, so it is a discontinuity. (x-3) only appears in the denominator, so it is an asymptote.
To find where on the x-axis a discontinuity or asymptote falls, set the factor equal to zero.
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