SOLUTION: What is the phase shift of y = -sec(4x + π)?

Algebra ->  Trigonometry-basics -> SOLUTION: What is the phase shift of y = -sec(4x + π)?      Log On


   

Question 753937: What is the phase shift of y = -sec(4x + π)?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the phase shift of y = -sec(4x + π)?
Basic equation for sec: y=sec(Bx-C), period=2π/B, phase shift (C/B)
For given equation:
B=4
C=π
phase shift=C/B=π/4 (shift to the left)