Question 753694: The x-intercepts of the graph are (3,0) ,(2,0) and
(8,0). The y-intercept is (0,1). However the given graph is a 4th degree polynomial function pointing down.
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The x-intercepts of the graph are (3,0) ,(2,0) and
(8,0). The y-intercept is (0,1). However the given graph is a 4th degree polynomial function pointing down.
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Comment: One of those x-intercepts must have multiplicity 2.
Since the function is 4th degree and opens down I think the
(3,0) must have multiplicty 2.
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If so, you get:
f(x) = a(x-2)(x-3)^2(x-8)
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Since f(0) = 1, solve for "a":
f(0) = a(-2)(-3)^2(-8) = 1
a*16*9 = 1
a = 1/144
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Equation:
f(x) = (1/144)(x-2)(x-3)^2(x-8)
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Cheers,
Stan H.
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
What is your question?
What is it that you do not understand about what you are being asked to do?
What have you tried so far?
By the way, you need a 5th point if you hope to find a 4th degree polynomial that fits the points.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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