SOLUTION: completing the square for: x^2-8x-2y^2-12y-4=0

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Question 753610: completing the square for:
x^2-8x-2y^2-12y-4=0
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-8x-2y%5E2-12y-4=0 --> x%5E2-8x-2y%5E2-12y=4 --> x%5E2-8x%2B16-2y%5E2-12y-18=4%2B16-18 --> %28x%5E2-8x%2B16%29-2%28y%5E2%2B6y%2B9%29=4%2B16-18 --> %28x-4%29%5E2-2%28y%2B3%29%5E2=2
Now that the squares are completed, we could divide both sides of the equal sign by 2 to get
%28x-4%29%5E2-2%28y%2B3%29%5E2=2 --> %28x-4%29%5E2%2F2-%28y%2B3%29%5E2%2F1=1
and we would know that the equation represents a hyperbola with vertices at
(4-sqrt%282%29,-3) and (4%2Bsqrt%282%29,-3)