SOLUTION: Given log 2=.3010 and log 3=.4771, evaluate log 6 Can you multiply the logs to get the value of log 6, so log 2 × log 3 .3010×.4771=.14361 Log 6=.14361 ?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Given log 2=.3010 and log 3=.4771, evaluate log 6 Can you multiply the logs to get the value of log 6, so log 2 × log 3 .3010×.4771=.14361 Log 6=.14361 ?      Log On


   

Question 753589: Given log 2=.3010 and log 3=.4771, evaluate log 6
Can you multiply the logs to get the value of log 6, so log 2 × log 3
.3010×.4771=.14361
Log 6=.14361 ?
Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Given log 2=.3010 and log 3=.4771, evaluate log 6
Can you multiply the logs to get the value of log 6, so log 2 × log 3
.3010×.4771=.14361
Log 6=.14361 ?

No, you cannot!!

You are correct that log 6 = log(2 * 3)

However, log (2 * 3) = log 2 + log 3, which calculates to: .301 + .4771, or highlight_green%28.7781%29

You can do the check!!

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