SOLUTION: -1 + ((x - b)( x - c ))/((a-b)(a-c)) +( (x - a)(x - b))/((c-a)(c-b)) +( (x - a)(x - c))/((b-a)(b-c)) I hope this makes sense from how I typed it. It needs to be simplified

Algebra ->  Expressions-with-variables -> SOLUTION: -1 + ((x - b)( x - c ))/((a-b)(a-c)) +( (x - a)(x - b))/((c-a)(c-b)) +( (x - a)(x - c))/((b-a)(b-c)) I hope this makes sense from how I typed it. It needs to be simplified      Log On


   



Question 753443:
-1 + ((x - b)( x - c ))/((a-b)(a-c)) +( (x - a)(x - b))/((c-a)(c-b)) +( (x - a)(x - c))/((b-a)(b-c))
I hope this makes sense from how I typed it. It needs to be simplified. I would really appreciate your help and direction.

Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
The simplification is relatively lengthy so I will outline it:
First off we set aside the -1 term and simplify the rational expression part.

the lcd is

(a-b)(a-c)(b-c)

After some labor we arrive at these results:
x^2 terms: 0
ax terms: abx-acx
bx terms: bcx-abx
cx terms: acx-bcx
bc terms: bc(b-c)
ab terms: ab(a-b)
ac terms: -ac(a-c)

After collecting like terms we find that all x-terms add out (cancel each other to get a sum of 0)

Leaving us with

ab(a-b)-ac(a-c)+bc(b-c)

which is equal to (a-b)(a-c)(b-c), the denominator!

Therefore our rational expression simplifies to 1 so that the entire expression evaluates to 0


:)