SOLUTION: Find the number of solutions of each equation. 1) x^2 + 8 = 0 2) 2x^2 + x = 0 3) 3x^2 - 9x = -5

Algebra ->  Systems-of-equations -> SOLUTION: Find the number of solutions of each equation. 1) x^2 + 8 = 0 2) 2x^2 + x = 0 3) 3x^2 - 9x = -5      Log On


   

Question 753258: Find the number of solutions of each equation.
1) x^2 + 8 = 0
2) 2x^2 + x = 0
3) 3x^2 - 9x = -5
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Any quadratic equation could have two or fewer solutions. Use the discriminant. Here is the systematic way:
DISCRIMINANT____ SOLUTIONS
positive______________2
zero________________1
negative____________0 (but there will be two imaginary or complex)