SOLUTION: Hello, I am stuck on this word problem and was hoping you could help me out here. I am usually pretty good with these sorts of problems, but I cannot get the formula to work righ

Algebra ->  Probability-and-statistics -> SOLUTION: Hello, I am stuck on this word problem and was hoping you could help me out here. I am usually pretty good with these sorts of problems, but I cannot get the formula to work righ      Log On


   

Question 752931: Hello, I am stuck on this word problem and was hoping you could help me out here.
I am usually pretty good with these sorts of problems, but I cannot get the formula to work right here.
Of the 65 students going on the soccer trip, 43 are players and 12 are left-handed. Only 5 of the left-handed students are soccer players. What is the probability that one of the students on the trip is a soccer player or is left-handed.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
P(Soccer Player OR Left Handed) = P(Soccer Player) + P(Left Handed) - P(Soccer Player AND Left Handed)


P(Soccer Player OR Left Handed) = 43/65 + 12/65 - 5/65


P(Soccer Player OR Left Handed) = (43 + 12 - 5)/65


P(Soccer Player OR Left Handed) = 50/65


P(Soccer Player OR Left Handed) = 10/13 <---- Probability as a fraction


P(Soccer Player OR Left Handed) = 0.769230769 <---- Probability as a decimal