SOLUTION: Se (f-1og)(x) = 2x2 + x - 6 e f(x) = x/2 + 3, então g(x) é dada por:

Algebra ->  Functions -> SOLUTION: Se (f-1og)(x) = 2x2 + x - 6 e f(x) = x/2 + 3, então g(x) é dada por:      Log On


   

Question 752830: Se (f-1og)(x) = 2x2 + x - 6 e f(x) = x/2 + 3, então g(x) é dada por:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
{f-log)? {f-g)? (f-10*g)??

Se system%28%28f-g%29%28x%29+=+2x%5E2+%2B+x+-+6%2Cf%28x%29+=+x%2F2+%2B+3%29 --> system%28f%28x%29-g%28x%29+=+2x%5E2+%2B+x+-+6%2Cf%28x%29+=+x%2F2+%2B+3%29 --> x%2F2+%2B+3-g%28x%29+=+2x%5E2+%2B+x+-+6 --> -g%28x%29+=+2x%5E2+%2B+x+-+6-x%2F2-3 --> -g%28x%29+=+2x%5E2+%2B+x%2F2+-+9 --> g%28x%29+=+-2x%5E2+-+x%2F2+%2B9