SOLUTION: logbase5(x+2)+logbase5(x-1)=2?? I tried solving it but I don't know If I am write I did (x+2)(x-1)=5^2 x+2=25(x-1) x+2=25x-25 -24x=-27 x=9/8???? I am I right? I think I am w

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: logbase5(x+2)+logbase5(x-1)=2?? I tried solving it but I don't know If I am write I did (x+2)(x-1)=5^2 x+2=25(x-1) x+2=25x-25 -24x=-27 x=9/8???? I am I right? I think I am w      Log On


   

Question 752738: logbase5(x+2)+logbase5(x-1)=2??
I tried solving it but I don't know If I am write
I did (x+2)(x-1)=5^2
x+2=25(x-1)
x+2=25x-25
-24x=-27
x=9/8????
I am I right? I think I am wrong
or is the problem even solvable?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
From the given, log%285%2C%28x%2B2%29%28x-1%29%29=2
5%5E2=%28x%2B2%29%28x-1%29
25=x%5E2%2Bx-2
x%5E2%2Bx-27=0

x=%28-1%2B-+sqrt%281%2B4%2A27%29%29%2F2
highlight%28x=%28-1%2B-+sqrt%28109%29%29%2F2%29