SOLUTION: The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches.
Please tell how this is done thanks
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-> SOLUTION: The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches.
Please tell how this is done thanks
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Question 752562: The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches.
Please tell how this is done thanks Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches.
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Let width be "x":
Then length will be "x+6":
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Equation:
Area = length*width
A(x) = x(x+6) = 91
x^2 + 6x - 91 = 0
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x^2 + 13x - 7x -91 = 0
x(x+13)-7(x+13) = 0
(x+13)(x-7) = 0
Positive solution:
x = 7 inches (width)
x+6 = 13 inches (length)
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Cheers,
Stan H.
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