SOLUTION: 1. The equation of an ellipse is given by (x+2)^2/49 + (y-4)^2/25=1 . a.) Identify the coordinates of the center of the ellipse. b.) Find the lengths of the major and minor axes

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 1. The equation of an ellipse is given by (x+2)^2/49 + (y-4)^2/25=1 . a.) Identify the coordinates of the center of the ellipse. b.) Find the lengths of the major and minor axes      Log On


   



Question 752171: 1. The equation of an ellipse is given by (x+2)^2/49 + (y-4)^2/25=1 .
a.) Identify the coordinates of the center of the ellipse.
b.) Find the lengths of the major and minor axes.
c.) Graph the ellipse.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
1. The equation of an ellipse is given by (x+2)^2/49+(y-4)^2/25=1.
Given ellipse has a horizontal major axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1, a>b, (h,k)=(x,y) coordinates of center.
..
a.) Identify the coordinates of the center of the ellipse.
center: (-2,4)
b.) Find the lengths of the major and minor axes.
a^2=49
a=√49=7
length of major axis=2a=14
b^2=25
b=5
length of minor axis=2b=10
c.) Graph the ellipse
see graph below:
(25-25(x+2)^2/49)^.5+4