SOLUTION: 4. A crowd contains 1000 people. 480 males and 520 females. Find the likelihood someone chosen at random is Female. 5. Using the information from #4, find the probability that two

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Question 751660: 4. A crowd contains 1000 people. 480 males and 520 females. Find the likelihood someone chosen at random is Female.
5. Using the information from #4, find the probability that two people chosen at random without replacement are both females.
6. Using the information from #4, four people are chosen with replacement. Find the probability that they are chosen by gender EXACTLY in order as FFMM.
7. Using the information from #4, find the probability that two people are chosen without replacement that have the same gender.

Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

4.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
4. A crowd contains 1000 people. 480 males and 520 females. Find the likelihood someone chosen at random is Female.
P(female) = 520/1000 = 0.52
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5. Using the information from #4, find the probability that two people chosen at random without replacement are both females.
Ans: 520C2/100C2 = 0.2702
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6. Using the information from #4, four people are chosen with replacement. Find the probability that they are chosen by gender EXACTLY in order as FFMM.
Ans: (1/2)^4 = 1/16
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7. Using the information from #4, find the probability that two people are chosen without replacement that have the same gender.
Ans: [480C2 + 520C2]/1000C2 = 134940/499500 = 0.2702
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Cheers,
Stan H.
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