Question 751636: Calculate the area of the triangle with the following vertices:
5. (0,-9), (3,-9), and (0,-2)
6. (-8, -2), (-1, -11), and (-1, -2)
7. (-5, 1), (2, 9), and (-5, 9)
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
In each case, you have two equal x coordinates and two equal y coordinates, therefore, two of the sides are perpendicular.
In each case, plot the points, draw your triangle, determine the length of the two perpendicular legs, multiply and then divide by 2, just like finding the area of any other right triangle.
Since the perpendicular legs are parallel to the axes, determining the length is a simple matter of subtracting coordinates and then taking the absolute value. For example, the measure of the segment that joins (0, -9) and (3, -9) is |0 - 3| = 3.
You can figure the rest for yourself. By the way, please read the instruction that says "One question per post." Then re-read it. Repeat until understanding is complete. Thank you.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
|
|
|
