SOLUTION: {{{ y=|x-1|+2}}}

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Question 751535: +y=%7Cx-1%7C%2B2
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Instead of this result, +y=%7Cx-1%7C%2B2, use the absolute value portion of function as abs() and then put the tags around the whole function equation:

y=abs(x-1)+2, and with the triple braces,
y=abs%28x-1%29%2B2.

Critical point is at x=1.
at x%3C1, x-1%3C0 and y=1-x%2B2 or y=-x%2B3.
At x%3E=1, y=x-1%2B2, or y=x%2B1.

SUMMARY:
You will graph for x%3C1, y=-x%2B3
and for x%3E=1, y=x%2B1