SOLUTION: What is the perimeter and area of a 45°-45°-90° triangle with a hypotenuse length of 12 feet

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Question 751139: What is the perimeter and area of a 45°-45°-90° triangle with a hypotenuse length of 12 feet
Found 2 solutions by rfer, Cromlix:
Answer by rfer(16322) About Me  (Show Source):
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Using trigonometric ratios with
the right angle triangle.
Using cos = adjacent/hypotenuse
cos 45 = adjacent/12
Adjacent = 12*cos45 = 8.5 feet (1 decimal place)
Using sin = opposite/hypotenuse
sin45 = opposite/12
Opposite = 12*sin45 = 8.5 feet (1 decimal place)

Perimeter =
8.5 + 8.5 + 12 = 29 feet
Area of triangle = 1/2(b*h)
1/2(8.5*8.5)
= 36.1 ft^2
Hope this helps
:-)