SOLUTION: Plz help solve for x if 2^(x+1) - 6^x = 2^(x-1), 3^x + 3^-x = 4 & dis 1 plz 2logbase3 (x+2)=2+logbase3 x?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Plz help solve for x if 2^(x+1) - 6^x = 2^(x-1), 3^x + 3^-x = 4 & dis 1 plz 2logbase3 (x+2)=2+logbase3 x?      Log On


   

Question 751134: Plz help solve for x if 2^(x+1) - 6^x = 2^(x-1), 3^x + 3^-x = 4 & dis 1 plz 2logbase3 (x+2)=2+logbase3 x?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!










Take the log of both sides, any base...







Which is the exact answer. Use your calculator for a numerica approximation. If you don't care about the numeric approximation, you can use base 3 logs so that your denominator becomes 1.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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