Question 751110: 3y+8=7-4y
Answer by lenny460(1073)   (Show Source):
You can put this solution on YOUR website! 3y + 8 = 7 - 4y
Add 4y to each side of the equation.
3y + 8 + 4y = 7 - 4y + 4y
Combine like terms:
3y + 4y = 7y
-4y + 4y = 0
Therefore:
7y + 8 = 7
Subtract 8 from each side of the equation.
7y + 8 - 8 = 7 - 8
8 - 8 = 0
7 - 8 = -1
7y = -1
Divide each side by 7
y = -1/7
Answer:
y = -1/7
Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: obuong3@aol.com
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