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Question 751087: a) Find the intersection point for equations 5x + 3y = 12 and 10x – 2y = 8.
b) Find the equation of a straight line with slope 0.60 that passes through point (5, 8).
c) Given two points C (1, 6) and H (3, 10). Determine the equation of a straight line that passes through them.
d) Find an equation of a straight line that passes through point (3, 6) and is parallel to line 6y + 2x = 18.
e) Find an equation of a straight line that passes through point (-2, 3) and is perpendicular to line y - 8x = 3.
Answer by nant_87(1)   (Show Source):
You can put this solution on YOUR website! There are two unknowns in these equations. We must eliminate one of the unknowns. We want to get rid of the x. The lowest common multiple of 5x and 10x is 10x.
5x + 3y = 12
10x – 2y = 8 multiply by 2
10x + 6y = 24
10x - 2y = 8 We must subtract these equations so we can get rid of the x's. To do this we change the sign of the lower one and add
10x + 6y = 24
- 10x + 2y = -8
8y = 16
y = 2
==> y=2 We plug this 2 in for Y on top equation *
5x + 3y = 12
5x + 3(2) = 12
x = 6/5
==> x = 6/5 The point of intersection is (6/5,2)
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