SOLUTION: lne^(x^2+3x-4)=ln5

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Question 750964: lne^(x^2+3x-4)=ln5
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
lne^(x^2+3x-4)=ln5
log of base raised to exponent=exponent
(x^2+3x-4)=ln5
(x^2+3x-4)=ln(5)≈1.6094
x^2+3x-4-1.6094=0
x^2+3x-5.6094=0
use quadratic formula to solve for x
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=1, b=3, c=5.6094
x≈1.3035
or
x≈-4.3035