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√3x·√51x
Break the 51 down to 3·17
√3x·√3·17x
Multiply under the radicals:
√3·3·17x²
√3²·17x²
Take out 3² as just a 3 in front of the radical.
Take out x² as just as |x| in front of the radical.
We must put the x between absolute value bars because the
original problem is the product of two radical square roots,
which are never negative, therefore the answer cannot be negative.
But x is a variable so it might be negative. So to assure that the
answer is not negative we must put absolute value bars around
x.
Answer:
3|x|√17
Edwin
