SOLUTION: A rectangular parking lot covers an area of 1150 square feet. It is 20 feet longer than it is wide. An equation appropriate for finding the dimensions of the lot is:

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Question 750867: A rectangular parking lot covers an area of 1150 square feet. It is 20 feet longer than it is wide. An equation appropriate for finding the dimensions of the lot is:
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
We can solve this with just one variable.
The short side is X, the long side is X+20
(X)(X+20)=1150
X%5E2%2B20X=1150
X%5E2%2B20X-1150=0
The quadratic solver yields
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve x%5E2%2B20%2Ax-1150=0 ( notice a=1, b=20, and c=-1150)





x+=+%28-20+%2B-+sqrt%28+%2820%29%5E2-4%2A1%2A-1150+%29%29%2F%282%2A1%29 Plug in a=1, b=20, and c=-1150




x+=+%28-20+%2B-+sqrt%28+400-4%2A1%2A-1150+%29%29%2F%282%2A1%29 Square 20 to get 400




x+=+%28-20+%2B-+sqrt%28+400%2B4600+%29%29%2F%282%2A1%29 Multiply -4%2A-1150%2A1 to get 4600




x+=+%28-20+%2B-+sqrt%28+5000+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)




x+=+%28-20+%2B-+50%2Asqrt%282%29%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%28-20+%2B-+50%2Asqrt%282%29%29%2F2 Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


x+=+%28-20+%2B+50%2Asqrt%282%29%29%2F2 or x+=+%28-20+-+50%2Asqrt%282%29%29%2F2



Now break up the fraction



x=-20%2F2%2B50%2Asqrt%282%29%2F2 or x=-20%2F2-50%2Asqrt%282%29%2F2



Simplify



x=-10%2B25%2Asqrt%282%29 or x=-10-25%2Asqrt%282%29



So the solutions are:

x=-10%2B25%2Asqrt%282%29 or x=-10-25%2Asqrt%282%29




And the first answer is positive. The second side is 20 feet longer.