SOLUTION: Use the quadratic formula to solve each of the following quadratic equations. {{{2x^2-5x=3}}} I needed to check my answer of: {{{x=2sqrt(73+5)/4}}},x={{{-2sqrt(73+5)/4}}}. Is t

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Use the quadratic formula to solve each of the following quadratic equations. {{{2x^2-5x=3}}} I needed to check my answer of: {{{x=2sqrt(73+5)/4}}},x={{{-2sqrt(73+5)/4}}}. Is t      Log On


   

Question 75083This question is from textbook Beginning Algebra
: Use the quadratic formula to solve each of the following quadratic equations.
2x%5E2-5x=3
I needed to check my answer of: x=2sqrt%2873%2B5%29%2F4,x=-2sqrt%2873%2B5%29%2F4. Is this correct? Thanks. This question is from textbook Beginning Algebra

Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
The quadratic equation is 2x%5E2-5x-3=0.
Comparing with ax%5E2%2Bbx%2Bc=0, a = 2, b = -5, c = -3.
The quadratic formula is
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
So here x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%2A2%2A%28-3%29+%29%29%2F%282%2A2%29+
x+=+%285+%2B-+sqrt%28+25%2B4%2A2%2A3+%29%29%2F4+
x+=+%285+%2B-+sqrt%28+25%2B24+%29%29%2F4+
x+=+%285+%2B-+sqrt%28+49+%29%29%2F4+
x+=+%285+%2B-+7%29%2F4+
Either x+=+%285+%2B+7%29%2F4+ or x+=+%285+-+7%29%2F4+
Either x+=+12%2F4+ or x+=+-2%2F4+
Either x+=+3+ or x+=+-1%2F2+

Your answer is wrong!

Remark: Check the answer by factoring [Hint: (2x+1)(x-3) = 0].