Question 750773: Suppose Tom has 26 coins totaling $4.40. If he has only dimes and quarters, how many of each type does he have? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! x = dimes and y = quarters
Form two equations relating:
1) The number of coins
2) the value of the coins
x + y = 26 ....1
10x + 25y = 440....2
Multiply (1) by 25
25x + 25y = 650
10x + 25y = 440
Subtract
15x = 210
x = 14
Substitute x = 14 into Equation 1
x + y = 26
14 + y = 26
y = 26 -14
y = 12
So you have 14 dimes and 12 quarters
