SOLUTION: factor by grouping, if possible, and check w^3 + 7w^2 + 4w + 28 Factor completely. If a polynomial is prime, state this 25a^2 - 23a

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Question 750581: factor by grouping, if possible, and check
w^3 + 7w^2 + 4w + 28
Factor completely. If a polynomial is prime, state this
25a^2 - 23a - 2
Found 2 solutions by stanbon, dkppathak:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
factor by grouping, if possible, and check
w^3 + 7w^2 + 4w + 28
w^2(w+7)+4(w+7)
= (w+7)(w^2+4)
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Factor completely. If a polynomial is prime, state this
25a^2 - 23a - 2
25a^2 - 25a+2a -2
----
25a(a-1)+2(a-1)
----
= (a-1)(25a+2)
=================
Cheers,
Stan H.
============

Answer by dkppathak(439) (Show Source):
You can put this solution on YOUR website!
w^3 + 7w^2 + 4w + 28
w^3 + 4w + 7w^2 + 28
w(w^2 +4)+7(w^2 +4)
(w^2 +4 )(w+7)answer
25a^2-23a-2
25a^2 -25a +2a -2
25a(a -1)-2(a-1)
(a-1)(25a -2) answer

SOLUTION: factor by grouping, if possible, and check w^3 + 7w^2 + 4w + 28 Factor completely. If a polynomial is prime, state this 25a^2 - 23a - 2