SOLUTION: Write an exponential function whose graph passes through the points (0, -6) and (-2, -54)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Write an exponential function whose graph passes through the points (0, -6) and (-2, -54)      Log On


   

Question 750564: Write an exponential function whose graph passes through the points (0, -6) and (-2, -54)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, -6) and (x2, y2) = (-2, -54).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-54--6%29%2F%28-2-0%29+=+24.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 24%2A0+%2Bb+=+-6. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-6-24%2A0+=+-6.

y=(24)x + (-6)

Your graph:





y=24x+-6

since you can't see second point on graph above, here is another graph: