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Question 75053: Stan thanks for your help ,i have 20 of these to do can you please help me thanks a millon .
2. Find the equation of the line with a slope of -5 and passes through the point (2, -4).
3. Write an equation of the line that passes through (0, -4) and is parallel y = (3/4)x + 2. Write the answer in slope-intercept form.
4. Solve the system of equations by substitution:
x + 2y = 9
3x - y = 13
5. Solve the system of equations by substitution:
4x - 3y = 1
12x - 9y = 3
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 2. Find the equation of the line with a slope of -5 and passes through the point (2, -4).
Form:y=mx+b ; -4=-5*2+b ; b=6
EQUATION: y=-5x+6
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3. Write an equation of the line that passes through (0, -4) and is parallel y = (3/4)x + 2. Write the answer in slope-intercept form.
slope = 3/4 to be parallel; y=mx+b ; -4=(3/4)*0+b ; b=-4
EQUATION:
y=(3/4)x-4
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4. Solve the system of equations by substitution:
x + 2y = 9
3x - y = 13
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x=9-2y
3(9-2y) - y = 13
27-6y -y = 13
7y=14
y=2
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x=9-2*2=5
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So, x=5 and y=2
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5. Solve the system of equations by substitution:
4x - 3y = 1
12x - 9y = 3
y=(4/3)x-1/3
12x - 9((4/3)x-(1/3)) = 3
12x-12x+3 = 3
3=3
This means the two equations are dependent. The two
equations are the equation of the same line. The solution
is every point of the line y=(4/3)x-(1/3)
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Cheers,
Stan H.
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