Question 75052: Give the vertices of the hyperbola (x-12)^2/16 - (y-14)^2/25 = 1
I have choices for answers that are:
a.) V(12+-3,14)
b.) V(12+-4,14)
c.) V(12,14+-3)
d.) V(12,14+-5)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Give the vertices of the hyperbola (x-12)^2/16 - (y-14)^2/25 = 1
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The center is at (12,14)
The semi-major axis is sqrt25=5 and that axis is vertical.
Vertices on the major axis are (12, 14+5)=(12,19) and (12,14-5)=(12,9)
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The semi-minor axis is sqrt16=4 and that axis is horizontal.
Vertices on the minor axis are (12+4,14)=(16,14) and (12-4,14)=(8,14)
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Cheers,
Stan H.
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