SOLUTION: (2ag squared) to the fourth power times (3a squared g cubed) squared

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Question 750501: (2ag squared) to the fourth power times (3a squared g cubed) squared
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
(2ag^2)^4*(3a^2g^3)^2

2^4*a^4*(g^2)^4*(3^2)*(a^2)^2*(g^3)^2

16*a^4*(g^2)^4*9*(a^2)^2*(g^3)^2

16*9*a^4*(g^2)^4*(a^2)^2*(g^3)^2

144*a^4*(g^2)^4*(a^2)^2*(g^3)^2

144*a^4*g^(2*4)*a^(2*2)*g^(3*2)

144*a^4*g^8*a^4*g^6

144*(a^4*a^4)*(g^8*g^6)

144*a^(4+4)*g^(8+6)

144*a^8*g^14

Final Answer: 144*a^8*g^14