SOLUTION: how can i solve this quadratic equation? 4x^2=13x+12

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Question 75039: how can i solve this quadratic equation?
4x^2=13x+12
Found 2 solutions by checkley75, Earlsdon:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2=13x+12
4x^2-13x-12=0
(4x+3)(x-4)=0
4x+3=0
4x=-3
x=-3/4 answer.
x-4=0
x=4 answer.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You can solve this quadratic equation by factoring.
4x%5E2+=+13x%2B12 First, rewrite in standard form.
4x%5E2-13x-12+=+0 Now factor.
%284x%2B3%29%28x-4%29+=+0 Apply the zero product principle.
4x%2B3+=+0 and/or x-4+=+0
If 4x%2B3+=+0 then 4x+=+-3 so x+=+-3%2F4
If x-4+=+0 then x+=+4
The roots are:
x+=+-3%2F4
x+=+4