SOLUTION: find three consecutive integers such that the first increased by twice the second exceeds the third by 24

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Question 750377: find three consecutive integers such that the first increased by twice the second exceeds the third by 24
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
(duplicate question)

consecutive integers: (x-1), x, (x+1)
(x-1) + 2x = (x+1) + 24
3x - 1 = x + 25
2x = 26
x = 13
The integers are 12, 13, and 14.