SOLUTION: pls i need help
At an airport, a flight controller was in a tower 40m above the ground. When she first observed a plane it was at an angle of elevation of 12 (degrees) from her
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At an airport, a flight controller was in a tower 40m above the ground. When she first observed a plane it was at an angle of elevation of 12 (degrees) from her
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Question 750324: pls i need help
At an airport, a flight controller was in a tower 40m above the ground. When she first observed a plane it was at an angle of elevation of 12 (degrees) from her line of sight and flying at a constant altitude (height)
The plane had a constant speed of 360km/h
Eight seconds later the plane flew directly overhead.
On reaching the tower, the plane climbed for the next 15 seconds, without changing speed, to reach a new altitude of 1500 meters above the ground.
What was the plane's angle of ascent during this time?
i dont know if i have to convert the velocity to m/s. i got the final answer and it's 59degrees im really not sure about my answer
can u please clarify the solutions u get thanks very much Answer by dkppathak(439) (Show Source):
You can put this solution on YOUR website! speed 360km/h
convert into m/s=100m/s
air craft travels for 8 sec to come overhead
distance traveled in 8 sec=800 m
it means aircraft was 800 m away at 12 degree from tower to altitude of aircraft
using trigonometry
we can say tan 12 = altitude of air craft/800
altitude of air craft from tower = 800x0.212 =169.6 m
as we know tan 12 =0.212
altitude of aircraft from ground= 169.6+40 =209.6 m
from over head of tower let elevation ang is x degree
it travel 15 sec at x degree to gain altitude upto 1500 m
difference of altitude gain by aircraft in 15 sec after tower =1500-209.6=1290.4
sin x=1290.4/1500=0.926
sin x=0.926
x= sin inverse of 0.926 =67.81 degree
answer 67.81 degree
