SOLUTION: five apples, 7 oranges, and 4 peaches are mixed in a fruit bin. If 4 pieces of fruit are picked out at random, what is the probability of picking 4 oranges OR 4 apples?
Algebra ->
Probability-and-statistics
-> SOLUTION: five apples, 7 oranges, and 4 peaches are mixed in a fruit bin. If 4 pieces of fruit are picked out at random, what is the probability of picking 4 oranges OR 4 apples?
Log On
Question 750258: five apples, 7 oranges, and 4 peaches are mixed in a fruit bin. If 4 pieces of fruit are picked out at random, what is the probability of picking 4 oranges OR 4 apples? Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! There are 16 fruits.
Oranges - 7/16 * 6/15 * 5/14 * 4/13 = (7*6*5*4)/(16*15*14*13)= 1/52 for the 4 oranges.
Apples - 5/16*4/15*3/14*2/13 = 1/364
we need to add these. 1/52 = 7/364 so it totals 8/364 or 2/91 or 2.2%
