SOLUTION: Write an equation in slope-intercept form for the line that satisfies the following condition. passes through (12, –4), perpendicular to the graph of y = 7/12x + 22

Algebra ->  Linear-equations -> SOLUTION: Write an equation in slope-intercept form for the line that satisfies the following condition. passes through (12, –4), perpendicular to the graph of y = 7/12x + 22      Log On


   

Question 750228: Write an equation in slope-intercept form for the line that satisfies the following condition.
passes through (12, –4), perpendicular to the graph of y = 7/12x + 22
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The given equation has slope = +7%2F12+
The slope of any line perpendicular to this one
will have slope = +-1%2Fm+
+-1+%2F+%287%2F12%29+=+-12%2F7+
-----------------------
( 12, -4 )
Using the general point-slope formula:
+%28+y+-+%28-4%29+%29+%2F+%28+x+-+12+%29+=+-12%2F7+
+%28+y+%2B+4+%29+%2F+%28+x+-+12+%29+=+-12%2F7+
+7%2A%28+y+%2B+4+%29+=+-12%2A%28+x+-+12+%29+
+7y+%2B+28+=+-12x+%2B+144+
+7y+=+-12x+%2B+116+
+y+=+%28-12%2F7%29%2Ax+%2B+116%2F7+
-------------------------
check:
Does it go through ( 12, -4 ) ?
+-4+=+%28-12%2F7%29%2A12+%2B+116%2F7+
+-4%2A7+=+-144+%2B+116+
+-28+=+-28+
OK