SOLUTION: solve each system by the elimination method or a combination of the elimination and substitution methods.
1) 3x^2+2y^2=12
2) x^2+2y^2=4
Algebra ->
Systems-of-equations
-> SOLUTION: solve each system by the elimination method or a combination of the elimination and substitution methods.
1) 3x^2+2y^2=12
2) x^2+2y^2=4
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Question 750197: solve each system by the elimination method or a combination of the elimination and substitution methods.
1) 3x^2+2y^2=12
2) x^2+2y^2=4 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 1) 3x^2+2y^2=12
2) x^2+2y^2=4
----------------- Subtract
2x^2 = 8
x^2 = 4
x = -2, +2
-----
y = 0
=============
(-2,0), (2,0)
